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X2+1=X+3
We move all terms to the left:
X2+1-(X+3)=0
We add all the numbers together, and all the variables
X^2-(X+3)+1=0
We get rid of parentheses
X^2-X-3+1=0
We add all the numbers together, and all the variables
X^2-1X-2=0
a = 1; b = -1; c = -2;
Δ = b2-4ac
Δ = -12-4·1·(-2)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-3}{2*1}=\frac{-2}{2} =-1 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+3}{2*1}=\frac{4}{2} =2 $
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