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X2+1X-202=0
We add all the numbers together, and all the variables
X^2+X-202=0
a = 1; b = 1; c = -202;
Δ = b2-4ac
Δ = 12-4·1·(-202)
Δ = 809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{809}}{2*1}=\frac{-1-\sqrt{809}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{809}}{2*1}=\frac{-1+\sqrt{809}}{2} $
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