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X2+20X=-75
We move all terms to the left:
X2+20X-(-75)=0
We add all the numbers together, and all the variables
X^2+20X+75=0
a = 1; b = 20; c = +75;
Δ = b2-4ac
Δ = 202-4·1·75
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-10}{2*1}=\frac{-30}{2} =-15 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+10}{2*1}=\frac{-10}{2} =-5 $
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