X2+20x=25

Solution for X2+20x=25 equation:

X2+20X=25

We move all terms to the left:

X2+20X-(25)=0

We add all the numbers together, and all the variables

X^2+20X-25=0

a = 1; b = 20; c = -25;
Δ = b2-4ac
Δ = 202-4·1·(-25)
Δ = 500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{500}=\sqrt{100*5}=\sqrt{100}*\sqrt{5}=10\sqrt{5}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-10\sqrt{5}}{2*1}=\frac{-20-10\sqrt{5}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+10\sqrt{5}}{2*1}=\frac{-20+10\sqrt{5}}{2}
$