X2+23x-132=0

Solution for X2+23x-132=0 equation:

X2+23X-132=0

We add all the numbers together, and all the variables

X^2+23X-132=0

a = 1; b = 23; c = -132;
Δ = b2-4ac
Δ = 232-4·1·(-132)
Δ = 1057
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-\sqrt{1057}}{2*1}=\frac{-23-\sqrt{1057}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+\sqrt{1057}}{2*1}=\frac{-23+\sqrt{1057}}{2}
$