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X2+24X-2160=0
We add all the numbers together, and all the variables
X^2+24X-2160=0
a = 1; b = 24; c = -2160;
Δ = b2-4ac
Δ = 242-4·1·(-2160)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-96}{2*1}=\frac{-120}{2} =-60 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+96}{2*1}=\frac{72}{2} =36 $
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