X2+24x=-80

Solution for X2+24x=-80 equation:

X2+24X=-80

We move all terms to the left:

X2+24X-(-80)=0

We add all the numbers together, and all the variables

X^2+24X+80=0

a = 1; b = 24; c = +80;
Δ = b2-4ac
Δ = 242-4·1·80
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-16}{2*1}=\frac{-40}{2}
=-20
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+16}{2*1}=\frac{-8}{2}
=-4
$