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X2+25X+2=0
We add all the numbers together, and all the variables
X^2+25X+2=0
a = 1; b = 25; c = +2;
Δ = b2-4ac
Δ = 252-4·1·2
Δ = 617
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{617}}{2*1}=\frac{-25-\sqrt{617}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{617}}{2*1}=\frac{-25+\sqrt{617}}{2} $
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