X2+25x-116=0

Solution for X2+25x-116=0 equation:

X2+25X-116=0

We add all the numbers together, and all the variables

X^2+25X-116=0

a = 1; b = 25; c = -116;
Δ = b2-4ac
Δ = 252-4·1·(-116)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-33}{2*1}=\frac{-58}{2}
=-29
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+33}{2*1}=\frac{8}{2}
=4
$