X2+26x+160=0

Solution for X2+26x+160=0 equation:

X2+26X+160=0

We add all the numbers together, and all the variables

X^2+26X+160=0

a = 1; b = 26; c = +160;
Δ = b2-4ac
Δ = 262-4·1·160
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-6}{2*1}=\frac{-32}{2}
=-16
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+6}{2*1}=\frac{-20}{2}
=-10
$