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X2+26X+25=0
We add all the numbers together, and all the variables
X^2+26X+25=0
a = 1; b = 26; c = +25;
Δ = b2-4ac
Δ = 262-4·1·25
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-24}{2*1}=\frac{-50}{2} =-25 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+24}{2*1}=\frac{-2}{2} =-1 $
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