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X2+26X-120=0
We add all the numbers together, and all the variables
X^2+26X-120=0
a = 1; b = 26; c = -120;
Δ = b2-4ac
Δ = 262-4·1·(-120)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-34}{2*1}=\frac{-60}{2} =-30 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+34}{2*1}=\frac{8}{2} =4 $
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