X2+26x-2=56

Solution for X2+26x-2=56 equation:

X2+26X-2=56

We move all terms to the left:

X2+26X-2-(56)=0

We add all the numbers together, and all the variables

X^2+26X-58=0

a = 1; b = 26; c = -58;
Δ = b2-4ac
Δ = 262-4·1·(-58)
Δ = 908
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{908}=\sqrt{4*227}=\sqrt{4}*\sqrt{227}=2\sqrt{227}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-2\sqrt{227}}{2*1}=\frac{-26-2\sqrt{227}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+2\sqrt{227}}{2*1}=\frac{-26+2\sqrt{227}}{2}
$