X2+28x-603=0

Solution for X2+28x-603=0 equation:

X2+28X-603=0

We add all the numbers together, and all the variables

X^2+28X-603=0

a = 1; b = 28; c = -603;
Δ = b2-4ac
Δ = 282-4·1·(-603)
Δ = 3196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3196}=\sqrt{4*799}=\sqrt{4}*\sqrt{799}=2\sqrt{799}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-2\sqrt{799}}{2*1}=\frac{-28-2\sqrt{799}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+2\sqrt{799}}{2*1}=\frac{-28+2\sqrt{799}}{2}
$