X2+2x+5+3x+x-20=180

Solution for X2+2x+5+3x+x-20=180 equation:

X2+2X+5+3X+X-20=180

We move all terms to the left:

X2+2X+5+3X+X-20-(180)=0

We add all the numbers together, and all the variables

X^2+6X-195=0

a = 1; b = 6; c = -195;
Δ = b2-4ac
Δ = 62-4·1·(-195)
Δ = 816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{816}=\sqrt{16*51}=\sqrt{16}*\sqrt{51}=4\sqrt{51}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-4\sqrt{51}}{2*1}=\frac{-6-4\sqrt{51}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+4\sqrt{51}}{2*1}=\frac{-6+4\sqrt{51}}{2}
$