X2+2x-235=0

Solution for X2+2x-235=0 equation:

X2+2X-235=0

We add all the numbers together, and all the variables

X^2+2X-235=0

a = 1; b = 2; c = -235;
Δ = b2-4ac
Δ = 22-4·1·(-235)
Δ = 944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{944}=\sqrt{16*59}=\sqrt{16}*\sqrt{59}=4\sqrt{59}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-4\sqrt{59}}{2*1}=\frac{-2-4\sqrt{59}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+4\sqrt{59}}{2*1}=\frac{-2+4\sqrt{59}}{2}
$