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X2+2X-3599=0
We add all the numbers together, and all the variables
X^2+2X-3599=0
a = 1; b = 2; c = -3599;
Δ = b2-4ac
Δ = 22-4·1·(-3599)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{14400}=120$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-120}{2*1}=\frac{-122}{2} =-61 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+120}{2*1}=\frac{118}{2} =59 $
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