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X2+2X-35X^2=0
We add all the numbers together, and all the variables
-34X^2+2X=0
a = -34; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-34)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-34}=\frac{-4}{-68} =1/17 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-34}=\frac{0}{-68} =0 $
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