X2+2x-540=0

Solution for X2+2x-540=0 equation:

X2+2X-540=0

We add all the numbers together, and all the variables

X^2+2X-540=0

a = 1; b = 2; c = -540;
Δ = b2-4ac
Δ = 22-4·1·(-540)
Δ = 2164
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2164}=\sqrt{4*541}=\sqrt{4}*\sqrt{541}=2\sqrt{541}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{541}}{2*1}=\frac{-2-2\sqrt{541}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{541}}{2*1}=\frac{-2+2\sqrt{541}}{2}
$