X2+2x=18+5X

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Solution for X2+2x=18+5X equation:



X2+2X=18+5X
We move all terms to the left:
X2+2X-(18+5X)=0
We add all the numbers together, and all the variables
X2+2X-(5X+18)=0
We add all the numbers together, and all the variables
X^2+2X-(5X+18)=0
We get rid of parentheses
X^2+2X-5X-18=0
We add all the numbers together, and all the variables
X^2-3X-18=0
a = 1; b = -3; c = -18;
Δ = b2-4ac
Δ = -32-4·1·(-18)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-9}{2*1}=\frac{-6}{2} =-3 $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+9}{2*1}=\frac{12}{2} =6 $

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