If it's not what You are looking for type in the equation solver your own equation and let us solve it.
X2+2X=28
We move all terms to the left:
X2+2X-(28)=0
We add all the numbers together, and all the variables
X^2+2X-28=0
a = 1; b = 2; c = -28;
Δ = b2-4ac
Δ = 22-4·1·(-28)
Δ = 116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{116}=\sqrt{4*29}=\sqrt{4}*\sqrt{29}=2\sqrt{29}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{29}}{2*1}=\frac{-2-2\sqrt{29}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{29}}{2*1}=\frac{-2+2\sqrt{29}}{2} $
| 19=−9,5x319=-9,5x3 | | C2+2x+27=0 | | 3x-8=-12x | | (2*10)^2=x | | {xÎZ|x2=225} | | 2^(x+3)=2^x | | x^2+(2x^2)^2=500 | | x^2+(4x)^2=500 | | 10^2+(2*x)^2=500 | | 10^2+(2x)^2=500 | | 10^2+(2*10)^2=x | | 0.8x=2.8 | | 10^2+x=500 | | 10+8x=11x-6 | | 10+8n=11n-6 | | 10^2+2*10^2=x | | p=8/24 | | 3.7+10m=7.81 | | (2x+2x)^2=400 | | 5(y-2)-3=-3(-6y+9)-9y | | x^2+4x^2=500 | | x^2+(2x)^2=500 | | 5x-20=3x-16 | | x^2+2(x^2)=500 | | 56=3.14(3.125+2.125)+2x | | x+2x=22.36 | | x^2+2x^2=500 | | -8=4p+4 | | –3w–5=1 | | F(x)=4x^2-2x+4 | | 5000=2500+125t | | F(x)=|2x+3| |