X2+3(x-5)=3x+10

Solution for X2+3(x-5)=3x+10 equation:

X2+3(X-5)=3X+10

We move all terms to the left:

X2+3(X-5)-(3X+10)=0

We add all the numbers together, and all the variables

X^2+3(X-5)-(3X+10)=0

We multiply parentheses

X^2+3X-(3X+10)-15=0

We get rid of parentheses

X^2+3X-3X-10-15=0

We add all the numbers together, and all the variables

X^2-25=0

a = 1; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·1·(-25)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10}{2*1}=\frac{-10}{2}
=-5
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10}{2*1}=\frac{10}{2}
=5
$