X2+30x+225=16

Solution for X2+30x+225=16 equation:

X2+30X+225=16

We move all terms to the left:

X2+30X+225-(16)=0

We add all the numbers together, and all the variables

X^2+30X+209=0

a = 1; b = 30; c = +209;
Δ = b2-4ac
Δ = 302-4·1·209
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-8}{2*1}=\frac{-38}{2}
=-19
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+8}{2*1}=\frac{-22}{2}
=-11
$