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X2+30X=10800
We move all terms to the left:
X2+30X-(10800)=0
We add all the numbers together, and all the variables
X^2+30X-10800=0
a = 1; b = 30; c = -10800;
Δ = b2-4ac
Δ = 302-4·1·(-10800)
Δ = 44100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{44100}=210$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-210}{2*1}=\frac{-240}{2} =-120 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+210}{2*1}=\frac{180}{2} =90 $
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