X2+32x+68=0

Solution for X2+32x+68=0 equation:

X2+32X+68=0

We add all the numbers together, and all the variables

X^2+32X+68=0

a = 1; b = 32; c = +68;
Δ = b2-4ac
Δ = 322-4·1·68
Δ = 752
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{752}=\sqrt{16*47}=\sqrt{16}*\sqrt{47}=4\sqrt{47}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-4\sqrt{47}}{2*1}=\frac{-32-4\sqrt{47}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+4\sqrt{47}}{2*1}=\frac{-32+4\sqrt{47}}{2}
$