X2+39x+224=0

Solution for X2+39x+224=0 equation:

X2+39X+224=0

We add all the numbers together, and all the variables

X^2+39X+224=0

a = 1; b = 39; c = +224;
Δ = b2-4ac
Δ = 392-4·1·224
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-25}{2*1}=\frac{-64}{2}
=-32
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+25}{2*1}=\frac{-14}{2}
=-7
$