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X2+3=7+X
We move all terms to the left:
X2+3-(7+X)=0
We add all the numbers together, and all the variables
X2-(X+7)+3=0
We add all the numbers together, and all the variables
X^2-(X+7)+3=0
We get rid of parentheses
X^2-X-7+3=0
We add all the numbers together, and all the variables
X^2-1X-4=0
a = 1; b = -1; c = -4;
Δ = b2-4ac
Δ = -12-4·1·(-4)
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{17}}{2*1}=\frac{1-\sqrt{17}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{17}}{2*1}=\frac{1+\sqrt{17}}{2} $
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