X2+3x-4=64

Solution for X2+3x-4=64 equation:

X2+3X-4=64

We move all terms to the left:

X2+3X-4-(64)=0

We add all the numbers together, and all the variables

X^2+3X-68=0

a = 1; b = 3; c = -68;
Δ = b2-4ac
Δ = 32-4·1·(-68)
Δ = 281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{281}}{2*1}=\frac{-3-\sqrt{281}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{281}}{2*1}=\frac{-3+\sqrt{281}}{2}
$