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X2+40X-329=0
We add all the numbers together, and all the variables
X^2+40X-329=0
a = 1; b = 40; c = -329;
Δ = b2-4ac
Δ = 402-4·1·(-329)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-54}{2*1}=\frac{-94}{2} =-47 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+54}{2*1}=\frac{14}{2} =7 $
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