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X2+45X-4050=0
We add all the numbers together, and all the variables
X^2+45X-4050=0
a = 1; b = 45; c = -4050;
Δ = b2-4ac
Δ = 452-4·1·(-4050)
Δ = 18225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{18225}=135$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-135}{2*1}=\frac{-180}{2} =-90 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+135}{2*1}=\frac{90}{2} =45 $
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