X2+45x-4050=0

Solution for X2+45x-4050=0 equation:

X2+45X-4050=0

We add all the numbers together, and all the variables

X^2+45X-4050=0

a = 1; b = 45; c = -4050;
Δ = b2-4ac
Δ = 452-4·1·(-4050)
Δ = 18225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{18225}=135$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-135}{2*1}=\frac{-180}{2}
=-90
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+135}{2*1}=\frac{90}{2}
=45
$