X2+48x-324=0

Solution for X2+48x-324=0 equation:

X2+48X-324=0

We add all the numbers together, and all the variables

X^2+48X-324=0

a = 1; b = 48; c = -324;
Δ = b2-4ac
Δ = 482-4·1·(-324)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-60}{2*1}=\frac{-108}{2}
=-54
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+60}{2*1}=\frac{12}{2}
=6
$