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X2+48X-432=0
We add all the numbers together, and all the variables
X^2+48X-432=0
a = 1; b = 48; c = -432;
Δ = b2-4ac
Δ = 482-4·1·(-432)
Δ = 4032
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4032}=\sqrt{576*7}=\sqrt{576}*\sqrt{7}=24\sqrt{7}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-24\sqrt{7}}{2*1}=\frac{-48-24\sqrt{7}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+24\sqrt{7}}{2*1}=\frac{-48+24\sqrt{7}}{2} $
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