X2+4=(x+1)(x+3)

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Solution for X2+4=(x+1)(x+3) equation: 



X2+4=(X+1)(X+3)

We move all terms to the left:

X2+4-((X+1)(X+3))=0

We add all the numbers together, and all the variables

X^2-((X+1)(X+3))+4=0

We multiply parentheses ..

X^2-((+X^2+3X+X+3))+4=0



We calculate terms in parentheses: -((+X^2+3X+X+3)), so:

(+X^2+3X+X+3)

We get rid of parentheses

X^2+3X+X+3

We add all the numbers together, and all the variables

X^2+4X+3

Back to the equation:

-(X^2+4X+3)



We get rid of parentheses

X^2-X^2-4X-3+4=0

We add all the numbers together, and all the variables

-4X+1=0

We move all terms containing X to the left, all other terms to the right

-4X=-1

X=-1/-4

X=1/4

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