X2+4x-252=0

Solution for X2+4x-252=0 equation:

X2+4X-252=0

We add all the numbers together, and all the variables

X^2+4X-252=0

a = 1; b = 4; c = -252;
Δ = b2-4ac
Δ = 42-4·1·(-252)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-32}{2*1}=\frac{-36}{2}
=-18
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+32}{2*1}=\frac{28}{2}
=14
$