X2+4x=46

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Solution for X2+4x=46 equation:



X2+4X=46
We move all terms to the left:
X2+4X-(46)=0
We add all the numbers together, and all the variables
X^2+4X-46=0
a = 1; b = 4; c = -46;
Δ = b2-4ac
Δ = 42-4·1·(-46)
Δ = 200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{200}=\sqrt{100*2}=\sqrt{100}*\sqrt{2}=10\sqrt{2}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-10\sqrt{2}}{2*1}=\frac{-4-10\sqrt{2}}{2} $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+10\sqrt{2}}{2*1}=\frac{-4+10\sqrt{2}}{2} $

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