X2+5x-14=26

Solution for X2+5x-14=26 equation:

X2+5X-14=26

We move all terms to the left:

X2+5X-14-(26)=0

We add all the numbers together, and all the variables

X^2+5X-40=0

a = 1; b = 5; c = -40;
Δ = b2-4ac
Δ = 52-4·1·(-40)
Δ = 185
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{185}}{2*1}=\frac{-5-\sqrt{185}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{185}}{2*1}=\frac{-5+\sqrt{185}}{2}
$