X2+6X+C=13+c

Solution for X2+6X+C=13+c equation:

X2+6X+=13+X

We move all terms to the left:

X2+6X+-(13+X)=0

We add all the numbers together, and all the variables

X2+6X-(X+13)+=0

We add all the numbers together, and all the variables

X^2+6X-(X+13)=0

We get rid of parentheses

X^2+6X-X-13=0

We add all the numbers together, and all the variables

X^2+5X-13=0

a = 1; b = 5; c = -13;
Δ = b2-4ac
Δ = 52-4·1·(-13)
Δ = 77
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{77}}{2*1}=\frac{-5-\sqrt{77}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{77}}{2*1}=\frac{-5+\sqrt{77}}{2}
$