X2+6x=-3x+-20

Solution for X2+6x=-3x+-20 equation:

X2+6X=-3X+-20

We move all terms to the left:

X2+6X-(-3X+-20)=0

We add all the numbers together, and all the variables

X2+6X-(-3X-20)=0

We add all the numbers together, and all the variables

X^2+6X-(-3X-20)=0

We get rid of parentheses

X^2+6X+3X+20=0

We add all the numbers together, and all the variables

X^2+9X+20=0

a = 1; b = 9; c = +20;
Δ = b2-4ac
Δ = 92-4·1·20
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-1}{2*1}=\frac{-10}{2}
=-5
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+1}{2*1}=\frac{-8}{2}
=-4
$