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X2+7X-144=0
We add all the numbers together, and all the variables
X^2+7X-144=0
a = 1; b = 7; c = -144;
Δ = b2-4ac
Δ = 72-4·1·(-144)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-25}{2*1}=\frac{-32}{2} =-16 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+25}{2*1}=\frac{18}{2} =9 $
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