X2+7x-228=0

Solution for X2+7x-228=0 equation:

X2+7X-228=0

We add all the numbers together, and all the variables

X^2+7X-228=0

a = 1; b = 7; c = -228;
Δ = b2-4ac
Δ = 72-4·1·(-228)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-31}{2*1}=\frac{-38}{2}
=-19
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+31}{2*1}=\frac{24}{2}
=12
$