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X2+7X=6
We move all terms to the left:
X2+7X-(6)=0
We add all the numbers together, and all the variables
X^2+7X-6=0
a = 1; b = 7; c = -6;
Δ = b2-4ac
Δ = 72-4·1·(-6)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{73}}{2*1}=\frac{-7-\sqrt{73}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{73}}{2*1}=\frac{-7+\sqrt{73}}{2} $
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