X2+8=3x+36

Solution for X2+8=3x+36 equation:

X2+8=3X+36

We move all terms to the left:

X2+8-(3X+36)=0

We add all the numbers together, and all the variables

X^2-(3X+36)+8=0

We get rid of parentheses

X^2-3X-36+8=0

We add all the numbers together, and all the variables

X^2-3X-28=0

a = 1; b = -3; c = -28;
Δ = b2-4ac
Δ = -32-4·1·(-28)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-11}{2*1}=\frac{-8}{2}
=-4
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+11}{2*1}=\frac{14}{2}
=7
$