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X2+8X=99
We move all terms to the left:
X2+8X-(99)=0
We add all the numbers together, and all the variables
X^2+8X-99=0
a = 1; b = 8; c = -99;
Δ = b2-4ac
Δ = 82-4·1·(-99)
Δ = 460
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{460}=\sqrt{4*115}=\sqrt{4}*\sqrt{115}=2\sqrt{115}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{115}}{2*1}=\frac{-8-2\sqrt{115}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{115}}{2*1}=\frac{-8+2\sqrt{115}}{2} $
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