X2+96x+256=0

Solution for X2+96x+256=0 equation:

X2+96X+256=0

We add all the numbers together, and all the variables

X^2+96X+256=0

a = 1; b = 96; c = +256;
Δ = b2-4ac
Δ = 962-4·1·256
Δ = 8192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8192}=\sqrt{4096*2}=\sqrt{4096}*\sqrt{2}=64\sqrt{2}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-64\sqrt{2}}{2*1}=\frac{-96-64\sqrt{2}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+64\sqrt{2}}{2*1}=\frac{-96+64\sqrt{2}}{2}
$