X2+9=3(2x+3)

Solution for X2+9=3(2x+3) equation:

X2+9=3(2X+3)

We move all terms to the left:

X2+9-(3(2X+3))=0

We add all the numbers together, and all the variables

X^2-(3(2X+3))+9=0


We calculate terms in parentheses: -(3(2X+3)), so:

3(2X+3)

We multiply parentheses

6X+9

Back to the equation:

-(6X+9)


We get rid of parentheses

X^2-6X-9+9=0

We add all the numbers together, and all the variables

X^2-6X=0

a = 1; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·1·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*1}=\frac{0}{2}
=0
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*1}=\frac{12}{2}
=6
$