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X2+X2=120
We move all terms to the left:
X2+X2-(120)=0
We add all the numbers together, and all the variables
2X^2-120=0
a = 2; b = 0; c = -120;
Δ = b2-4ac
Δ = 02-4·2·(-120)
Δ = 960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{960}=\sqrt{64*15}=\sqrt{64}*\sqrt{15}=8\sqrt{15}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{15}}{2*2}=\frac{0-8\sqrt{15}}{4} =-\frac{8\sqrt{15}}{4} =-2\sqrt{15} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{15}}{2*2}=\frac{0+8\sqrt{15}}{4} =\frac{8\sqrt{15}}{4} =2\sqrt{15} $
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