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X2+X-9312=0
We add all the numbers together, and all the variables
X^2+X-9312=0
a = 1; b = 1; c = -9312;
Δ = b2-4ac
Δ = 12-4·1·(-9312)
Δ = 37249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{37249}=193$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-193}{2*1}=\frac{-194}{2} =-97 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+193}{2*1}=\frac{192}{2} =96 $
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