X2+y2-36=0

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Solution for X2+y2-36=0 equation:



X2+X2-36=0
We add all the numbers together, and all the variables
2X^2-36=0
a = 2; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·2·(-36)
Δ = 288
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{288}=\sqrt{144*2}=\sqrt{144}*\sqrt{2}=12\sqrt{2}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{2}}{2*2}=\frac{0-12\sqrt{2}}{4} =-\frac{12\sqrt{2}}{4} =-3\sqrt{2} $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{2}}{2*2}=\frac{0+12\sqrt{2}}{4} =\frac{12\sqrt{2}}{4} =3\sqrt{2} $

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