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X2+X2=106
We move all terms to the left:
X2+X2-(106)=0
We add all the numbers together, and all the variables
2X^2-106=0
a = 2; b = 0; c = -106;
Δ = b2-4ac
Δ = 02-4·2·(-106)
Δ = 848
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{848}=\sqrt{16*53}=\sqrt{16}*\sqrt{53}=4\sqrt{53}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{53}}{2*2}=\frac{0-4\sqrt{53}}{4} =-\frac{4\sqrt{53}}{4} =-\sqrt{53} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{53}}{2*2}=\frac{0+4\sqrt{53}}{4} =\frac{4\sqrt{53}}{4} =\sqrt{53} $
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