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X2+X2=1989
We move all terms to the left:
X2+X2-(1989)=0
We add all the numbers together, and all the variables
2X^2-1989=0
a = 2; b = 0; c = -1989;
Δ = b2-4ac
Δ = 02-4·2·(-1989)
Δ = 15912
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{15912}=\sqrt{36*442}=\sqrt{36}*\sqrt{442}=6\sqrt{442}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{442}}{2*2}=\frac{0-6\sqrt{442}}{4} =-\frac{6\sqrt{442}}{4} =-\frac{3\sqrt{442}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{442}}{2*2}=\frac{0+6\sqrt{442}}{4} =\frac{6\sqrt{442}}{4} =\frac{3\sqrt{442}}{2} $
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